0.6x^2+3.3x-2.1=-2.7

Solution for 0.6x^2+3.3x-2.1=-2.7 equation:

0.6x^2+3.3x-2.1=-2.7

We move all terms to the left:

0.6x^2+3.3x-2.1-(-2.7)=0

We add all the numbers together, and all the variables

0.6x^2+3.3x+0.6=0

a = 0.6; b = 3.3; c = +0.6;
Δ = b2-4ac
Δ = 3.32-4·0.6·0.6
Δ = 9.45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.3)-\sqrt{9.45}}{2*0.6}=\frac{-3.3-\sqrt{9.45}}{1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.3)+\sqrt{9.45}}{2*0.6}=\frac{-3.3+\sqrt{9.45}}{1.2}
$